X 5 2 X 3 5 1 2. This one is really easy if you just follow the basics of equations. Multiply the numerator of the first fraction by the denominator of the second. In the following intermediate step, it cannot further.
How much space down each square occupy on the graph paper?each. Step 1 :equation at the end of step 1 : Simplify the expression as follows:
X ≓ 1.284250617 step by step solution : Converting from decimals to fractions is straightforward. Multiply both numerators and denominators.
Result fraction keep to lowest possible denominator gcd (2, 15) = 1. Move the negative in front of the fraction. New numerator is 10 + 3 = 13.
B) add the answer from previous step 10 to the numerator 3. 3 · 5 = 2. In the graph paper taken, each side of each square measures 1em.
2x=5122 to the power of x equals 512take the log of both sides log10(2x)=log10(512) rewrite the left side of the equation using the rule for the log of a power x•log10(2)=log10(512) isolate the. A) multiply the whole number 2 by the denominator 5. Ncert solutions for class 12 physics;